To solve the system of equations:
Step 1: Write the equations clearly
[ \begin{cases} 2x + y = 5 \quad \text{(Equation 1)} \ 3x - y = 10 \quad \text{(Equation 2)} \end{cases} ]
Step 2: Eliminate (y) by adding the two equations
Adding Equation 1 and Equation 2:
[
(2x + y) + (3x - y) = 5 + 10 \
5x = 15 \
x = 3
]
Step 3: Substitute (x=3) into Equation 1 to find (y)
[ 2(3) + y = 5 \ 6 + y = 5 \ y = 5 - 6 = -1 ]
Answer: (x=3), (y=-1)
(\boxed{x=3, y=-1})

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